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<TITLE>Release 1.5.0b1 Phase-2 PMTU - Test #9 Host Test</TITLE>
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<P><FONT SIZE=2 FACE="Arial">Hello All,</FONT>
</P>
<P><FONT SIZE=2 FACE="Arial">There is a discrepancy in the test =
procedure diagram and description for this test. The MTU in the =
Packet Too Big message is actually 56 for this test, and not zero as =
shown in the procedure diagram.</FONT></P>
<P><FONT SIZE=2 FACE="Courier New"> =
TN2 &nbs=
p; =
TR1 &nbs=
p; NUT<BR>
=
| =
=
| =
|<BR>
=
|-------------------------------------------->|<BR>
| 1.Echo Request =
| =
|<BR>
| (1280 =
octets) =
| =
|<BR>
=
| =
=
| =
|<BR>
=
|<--------------------------------------------|<BR>
| 2.Echo =
Reply =
| =
|<BR>
| (1280 =
octets) =
| =
|<BR>
=
| =
=
| =
|<BR>
=
| =
=
+--------------------->|<BR>
=
| =
| 3.Packet =
Too Big |<BR>
=
| =
=
| (MTU =
0) |<BR>
=
| =
=
| =
|<BR>
=
|-------------------------------------------->|<BR>
| 4.Echo Request =
| =
|<BR>
| (1280 =
octets) =
| =
|<BR>
=
| =
=
| =
|<BR>
=
|<--------------------------------------------|<BR>
| 5.Echo =
Reply =
| =
|<BR>
| (1288 =
octets) =
| =
|<BR>
=
| =
=
| =
|<BR>
=
v =
=
v =
v</FONT>
</P>
<P><FONT SIZE=2 FACE="Arial">Also, can someone please explain to me =
why the NUT would echo 1288 bytes when it receives only 1280 =
bytes? I am referring to #4 and #5 of the above =
diagram.</FONT></P>
<P><FONT SIZE=2 FACE="Arial">I am having trouble understanding why =
this test expects the NUT to fragment the echo reply when the packet =
size is equal to the IPv6 minimum link MTU. We do not fragment =
until we reach the link MTU of 1500. Even if we set the link MTU =
to 1280, the IPv6 minimum link MTU, we should not fragment a 1280 byte =
echo reply packet. I'm sure I am overlooking something here. =
Your advice is greatly appreciated.</FONT></P>
<P><FONT SIZE=2 FACE="Arial">Best Regards,<BR>
Tammy Leino</FONT>
</P>
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